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nikdorinn [45]
3 years ago
12

Evan and Marshall are having a debate. Evan contends that the pantheon is larger than the pantheon in terms of area. Marshall co

ntends the opposite. To settle their debate, they find satellite images of both ancient temples and juxtaposed them on a single coordinate grid. Who should win the debate?
Mathematics
2 answers:
AlekseyPX3 years ago
7 0

Answer:

The area of the Pantheon is 2826. Round the final answer to the nearest square meter. Do not round intermediate calculations. The area of the Parthenon is 2000. Round the final answer to the nearest square meter. Do not round intermediate calculations.

The person who created the answers used 3.141 as pi and since nothing is said as what to use for pi I used 3.14 and that was really frustrating to me.

Thought you guys should know. And I want to also add thank you so much for the time and effort your team and volenters put into Khan I really appreciate it.

Credit- Andy

blondinia [14]3 years ago
6 0

Answer:

The area of the Pantheon is 2817 m squared

The area of the Parthenon is 2000 m squared

Evan should win the debate.

Step-by-step explanation:

Looking at the graph, the radius of the Pantheon is 30m, Let's find the area of the Pantheon, rounding our result to the nearest square meter. To determine the area of the Parthenon, we'll need to find its length and width. Let's use the distance formula to find the length (khan answer)

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A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Which statement about the quadrilateral is true?
Aleksandr-060686 [28]

Answer: A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Find:

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AKA your correct awnser choice is A :)✨

5 0
3 years ago
A cuboid in which the sum of its dimensions is 9 cm., then the sum of its edge lengths - cm. (18 or 27 or 36 or 45)​
ser-zykov [4K]

The number of sides or edges on a cuboid  are twelve, and the sum of the

edges is the sum of the twelve edges.

The sum of the edge lengths = <u>36 cm</u>

Reasons:

The given parameters are;

The sum of the dimension of the cuboid = 9 cm

Required:

The value sum of the dimension of the edges the cuboid.

Solution:

The dimensions of a cuboid are; Length, <em>l</em>, width, <em>w</em>, and height, <em>h</em>

We get;

l + w + h = 9

The number of times that each dimension appear = 4 times

4 edges with the same length as the height, <em>h</em>

4 edges with the same length as the width, <em>w</em>

4 edges with the same length as the length, <em>l</em>

The sum of the edge lengths is therefore; Sum Edges = 4·l + 4·w + 4·h

Which gives;

Sum Edges = 4·l + 4·w + 4·h = 4 × (l + w + h) = 4 × 9 = 36

The sum of the edge lengths = <u>36 cm</u>.

Learn more here:

brainly.com/question/12978944

5 0
3 years ago
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. Find the width and length.
Brums [2.3K]
Let the width = x
=>length = 2x-1

91= x(2x-1)=2x^2-x
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=(2x+13)(x-7)
=> x=-13/2=> no
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7 0
3 years ago
A self-serve car wash charges $5.81 to use its facilities, plus an additional $0.77 for each minute the customer is at the self-
Zigmanuir [339]

Answer:

C. $11.20.

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3 0
3 years ago
Which of the following best describes the solution to the system of equations below?
liraira [26]

For this case we have the following system of equations:

6x + 3y = 6\\6x + 3y = 14

We multiply the first equation by -1:

-6x-3y = -6

We have the following equivalent system:

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We add the equations:

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Equality is not fulfilled, so the system of equations has no solution.

Answer:

Option C

5 0
3 years ago
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