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Harlamova29_29 [7]
2 years ago
5

F(x)=Tan^-1 (1) PLEASE ANSWER! WILL GIVE BRAINLIEST

Mathematics
1 answer:
notka56 [123]2 years ago
5 0

Answer:

−π

----

4

Step-by-step explanation:

Alright, archtan /

tan

−

1

(

x

)

is the inverse of tangent. Tan is

sin

cos

. Like the inverse of sin, the inverse of tan is also restricted to quadrants 1 and 4.

Knowing this we are solving for the inverse of tan -1. We are basically being asked the question what angle/radian does tan(-1) equal. Using the unit circle we can see that tan(1)= pi/4.

Since the "Odds and Evens Identity" states that tan(-x) = -tan(x). Tan(-1)= -pi/4.

Knowing that tan is negative in quadrants 2 and 4. the answer is in either of those two quadrants. BUT!!! since inverse of tan is restricted to quadrants 1 and 4 we are left with the only answer -pi/4.

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goblinko [34]

Answer:-5x-8y=-5

Step-by-step explanation:

add right sides of equation and even them with result of adding right sides of equation

4x-4y-9x-4y=-2-3

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Answer:

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Step-by-step explanation:

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2 years ago
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djyliett [7]
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3 years ago
Read 2 more answers
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Firlakuza [10]

Answer:

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Step-by-step explanation:

\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}

To find the point of discontinuity :

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Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

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So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

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⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

4 0
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Usimov [2.4K]

Answer:

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I have attached a picture of the graph below.

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