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3 years ago

The speed of light in four different materials is shown below:

Chemistry

1 answer:

11Alexandr11 [23.1K]3 years ago

7 0

Material C. the less dense is easier to move through than the more dense, so the light moves faster. Its like light moving through less dense glass, then moving through a more dense wall.

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What is the most likely evidence of an energy transformation taking place when a skater glides over ice? A.Skating blades become

Diano4ka-milaya [45]

The correct answer is C. The weight downward and the friction moving forward creates thermal energy through kinetics and melts a tiny bit of the ice making it slick enough for the skate to slide.

7 0

4 years ago

What volume is occupied by a 0.118 mol of helium gas at a pressure of 0.97 atm and a temperature of 305 K ? Would the volume be

Naddika [18.5K]

Answer:

See below

Explanation:

PV = n RT R = .082057 L - Atm / (K-Mole)

.97 V = .118 (.082057)(305)

V = 3.04 liters

Will not change for argon.....will be the same for all ideal gases

5 0

2 years ago

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

A gas occupies a volume of 180 mL at 35oC and 740 mmHg. What is the volume of the gas at STP?

Tasya [4]

Answer:

there you go

Explanation:

6 0

3 years ago

Intact cells of two unknown cell types were placed into solutions with different concentrations of NaCl. Type I cells swelled an

Bess [88]

Answer:

Cell Type I: Animal cell surrounded by a plasma membrane only.

Cell Type II: Plant cell surrounded by a plasma membrane and a cell wall.

Explanation:

Hello,

In this case, we must remember that animal cells are covered only by a plasma membrane, which is not enough to keep the cell from bursting as no limit for the inlet salt is established, causing it both to swell and burst. On the other hand, plant cells are covered by both a plasma membrane and a cell wall which contributive effect allow the inlet of the salt but prevent the cell to burst as the cell wall is rigid. In such a way, based on the described situation, one infers that the cell type I is an animal cell surrounded by a plasma membrane only the cell type II is a plant cell surrounded by a plasma membrane and a cell wall.

Best regards.

3 0

3 years ago