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Andrei [34K]
3 years ago
10

Please help! This is due in less that 10 minutes! (Will mark Brainliest!)

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

<em>Answer: a = - 12</em>

Step-by-step explanation:

We have here two equations, one 18x + 12y = 36, the other ax - 8y = - 24;

Now if we were to consider making these two equations have a common y co - efficient, we would multiply the top equation by 2, the bottom consecutively by - 3. This would make a standard 24y ;

2 * ( 18x + 12y = 36 ),     ⇒       36x + 24y = 72

+ - 3 * (  ax - 8y = - 24 )            + - 3ax + 24y = 72

As you can see, all terms are equivalent, besides that of the co - efficient of x. Knowing that, it would be ax must be multiplied by - 3 to receive 36x, as the bottom equation is multiplied by - 3, where all terms are equivalent to the top terms;

- 3 * ax ⇒ 36x, - 3 * - 12x = 36x,

<em>Answer: a = - 12</em>

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Step-by-step explanation:

The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

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The only prime factors are 2 and 5.

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Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

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The goal is to find the possible values of k. Note that from integer division by 40,

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The inequality becomes:

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Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

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