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grandymaker [24]
3 years ago
6

A company claims that 5% of its products will be defective. A simple random sample of 300 products contain 10 defective products

. What is the probability that 10 or more defective products would have happened by random chance
Mathematics
1 answer:
Radda [10]3 years ago
3 0

Answer:

wateva

Step-by-step explanation:

wateva u want it too be good luck

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What is (4c-d+0.2)^2-10c; c=3.1, d=4.6​
yuradex [85]

Good evening ,

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Answer:

(4c-d+0.2)² - 10c = 33

___________________

Step-by-step explanation:

(4c-d+0.2)^2-10c

c=3.1, d=4.6​

(4(3.1) - 4.6 + 0.2)² - 10(3.1) = (12.4 - 4.6 + 0.2)² - 31 = (7.8 + 0.2)² -31 = 8² - 31 = 64-31 =33.

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8 0
3 years ago
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What is $0.8\%$ of $125\%$ of $8128$? Express your answer as a decimal.
Andre45 [30]

Answer:

<h2>81.28</h2>

Step-by-step explanation:

To solve this kind of problem, we must remember that the word "of" means multiplication in math language, and all percentages numbers can be expressed as a fraction where the denominator is 100. Applying all this, we have

0.8\%\times 125\%\times 8128\\\frac{0.8}{100}\times \frac{125}{100} \times 8128\\ 0.008(1.25)(8128)=81.28

Therefore, all those percentages of 8128 results in 81.28

5 0
3 years ago
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Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

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Answer:

21.

Step-by-step explanation:

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2 years ago
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