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Rudik [331]
2 years ago
8

Solve the following equation for p: 6/p=x+a

Mathematics
1 answer:
masya89 [10]2 years ago
6 0

\dfrac 6p = x+a\\\\\implies \dfrac 6p \times\dfrac  16 = (x+a) \times\dfrac 16 ~~~~~~;\left[\text{Multiply both sides by}~ \dfrac 16 \right]\\\\\implies \dfrac 1p = \dfrac{x+a}6\\\\\implies p= \dfrac{6}{x+a}~~~~~~~~~~~~~~~~~~~~;[\text{Cross multiply}]

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It’s linear so you map out the first differences and then put it into y=Mx+b form. For the you gotta find the y intercept
Alika [10]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's find the slope (m) :

  • \dfrac{y2 - y1}{x2 - x1}

  • \dfrac{16 - 11}{9 - 6}

  • \dfrac{5}{3}

slope of given line is 5/3

now, let's plug the value of coordinates of a point lying on the line ( for example : (6 , 11) and slope (m) to find the y - intercept (c) :

  • y = mx + c

  • 11 =   \bigg(\dfrac{5}{ 3}  \times 6 \bigg)  + c

  • 11 = (5 \times 2) + c

  • 11 = 10 + c

  • c = 11 - 10

  • c = 1

value of y - intercept (c) = 1, so our equation will be :

  • y = mx + c

  • y =  \dfrac{5}{3}x  + 1
6 0
2 years ago
Find the Volume: 3.2 cm<br> 7 cm<br> 4.8 cm
REY [17]
V = 0.5*b*h*l
v = 0.5*4.8*3.2*7
v = 0.5*107.52
v = 53.76cm3
7 0
3 years ago
A quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root. Write the equation in general form
andrey2020 [161]
<span>The general form of quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root
=> x = <u>-b  + </u></span><u>√ b^2 – 4 ac</u><span>
                    2a

It is also written as:
=> ax^2 + bx + c = 0

Quadratic equation involves unknown numbers which is x, the numbers which a, b and c are called coeffecients.
There are also quadratic factorization where you factor the polynomial give to be able to get the value of the equation.</span>



5 0
3 years ago
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Yuki888 [10]
M = 90 kg,
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1 N = 0.2248 lbf
333.9 · 0.2248 = 75.06072 lbf ≈ 75 lbf
5 0
3 years ago
Last week Mark ran 31 miles more than Jack. Mark ran 46 miles .How many miles did Jack run
Levart [38]
You take what Mark ran, 46 miles, and you see that Mark ran 31 more miles than Jack, so the equation would be 46-31, which would be 15 miles. So, Jack ran 15 miles.
8 0
3 years ago
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