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3 years ago

I need help on question 1 and 4

Mathematics

2 answers:

Crank3 years ago

8 0

Answer:

I only see question 4

Step-by-step explanation:

4) The rate change is going two units to the right and two units down.

ivolga24 [154]3 years ago

7 0

I believe the rate of change is -1

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Anton put 35 marbles equally into 5 jars. each jar holds either 5 large marbles or 7 small marbles. what size of marbles did Ant

eduard

Large marbles. 5x7=35

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3 years ago

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REY [17]

Answer:

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Step-by-step explanation:

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4 years ago

Leon correctly found the slope and y-intercept of the line that passes through the points (9, –8) and (3, 4) as follows.

Anna11 [10]

Answer:

$\displaystyle y = -2x + 10$

Step-by-step explanation:

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I am joyous to assist you anytime.

6 0

3 years ago

Find the exact value of csc 5pi/6

Leona [35]

Answer:

csc 2 (csc $\frac{5\pi}{6}$ = csc 150 = csc 30 = csc 2)

Step-by-step explanation:

csc $\frac{5\pi}{6}$ is in the 2nd Quadrant where only sin, and csc are positive.

csc $(\frac{5\pi}{6})=csc (\pi -(\frac{5\pi}{6}))=csc(\frac{5\pi}{6})$

but csc $\frac{5\pi}{6}$ = $\frac{1}{sin (\pi/6)} = \frac{1}{sin 30} = \frac{1}{1/2} =2$

7 0

3 years ago

Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1]

blagie [28]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

3 0

3 years ago