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3 years ago

7

ASAP i need this TODAY PLEASE)For a survey, students in a class answered these questions: Do you play a sport? Do you play a mus

ical instrument?
To the nearest percentage point, what percentage of students who play a sport don’t play a musical instrument?

1 answer:

kondaur [170]3 years ago

5 0

To the nearest percentage point, what percentage of students who play a sport don’t play a musical instrument?

First, using the information given, fill out the chart with the rest of the data (in the image attached)

Then find the number of students who play a sport and don’t play a musical instrument, which in the chart is 11

Place 11 over the total: $\frac{11}{25}$ and convert to a percentage:

44%

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2 years ago

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To get the that relates x and y, we choose two points on the table and use the equation of a straight line as follows:

Recall that the equation of a staight line is obtained from the formula
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Using the points (30, 18) and (36, 24), we have
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3 years ago

If f(x)=x/2-3and g(x)=4x^2+x-4, find (f+g)(x)

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2 years ago

A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud

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Answer:

$-0.048$

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Step-by-step explanation:

From the question we are told that

Sample size $n_1=350$

Sample size $n_2=250$

Sample proportion 1 $\hat P= \frac{25}{350} =>0.07$

Sample proportion 2 $\hat P= \frac{19}{250} =>0.076$

95% confidence interval

Generally for 95% confidence level

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$\alpha = 1-0.95=>0.05$

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Generally the equation for confidence interval between $P_1 - P_2$ is mathematically given as

$(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2} }$

$(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250} }$

$(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4 }$

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Therefore

Confidence interval is

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Given the confidence interval has zero

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2 years ago

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3 years ago