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2 years ago

What is the slope of the line that passes through the points

Mathematics

1 answer:

Jlenok [28]2 years ago

6 0

We are given:

The line passes through the points (9,4) and (9,-5)

We know that:

Slope of a line = (change in y) / (change in x)

Finding the slope:

Change in x = final x - initial x

Change in x = 9 - 9 = 0

Slope of line = (change in y) / 0

because division by 0 is undefined:

Slope of the line is Undefined

We could've solved for the change in y but there's no reason to because no matter what's in the numerator, as long as the denominator is 0, the value is undefined

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Find the amount of time. I = $60, P= $400, r = 5% Find how many years

Keith_Richards [23]

I=PRT

$60= 400 ×.05 × t

$60= 20× t

t= 60/20

3=t

4 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Len [333]

Answer:

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4} \implies 2^{-32}$

2. $2^4 . (2^2)^{-2} \implies 1$

3. $(-2^{-4}).(2^2)^0 \implies -2^8$

4. $(2^2).(2^3)^{-3} \implies 2^{-5}$

Step-by-step explanation:

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4}$ :

$= \frac{ ( - 2 ^ 2 ) ^ { - 6 } } { ( 2 ^ { - 5 } ) ^ { - 4 } } = \frac{2^{-12}}{2^{20}} = 2^{-12-20}=2^{-32}$

2. $2 ^ 4 . ( 2 ^ 2 ) ^ { - 2 }$ :

$= 2^4 \times \frac{1}{2^4} = 1$

3. $(-2^{-4}).(2^2)^0$ :

$= (-2^4)^2 \times 1 = -2^8$

4. $(2^2).(2^3)^{-3}$ :

$= 2^4 \times \frac{1}{2^9} =\frac{1}{2^5} =2^{-5}$

5 0

3 years ago

Read 2 more answers

Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h

irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = population proportion.

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, $H_0$ : p = 0.70 {means that the population proportion is equal to 0.70}

Alternate Hypothesis, $H_A$ : p < 0.70 {means that the population proportion is less than 0.70}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.63

n = sample of observations = 100

So, the test statistics = $\frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }$

= -1.528

The value of z-test statistics is -1.528.

Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

4 0

3 years ago

What equation is graphed in this figure?

Ksivusya [100]

to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

$(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})$

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.

7 0

2 years ago

PLZ HELP ASAP 20 POINTS WILL MARK BRAINLIEST THANK YOU

Ganezh [65]

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3 years ago

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