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Oxana [17]
3 years ago
6

What happens after a mass extinction, such as an ice age or the extinction of the dinosaurs? (

Biology
2 answers:
photoshop1234 [79]3 years ago
8 0
The surviving species evolve more rapidly
gizmo_the_mogwai [7]3 years ago
8 0

What happens after a mass extinction, such as an ice age or the extinction of the dinosaurs?

The surviving species evolve more rapidly to fill the newly available niches.

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What prevents organic molecules from forming on their own and remaining intact today?
loris [4]

Answer:

Atmospheric oxygen is too reactive

Explanation:

4 0
3 years ago
Which statement best explains why muscle cells and skin cells do not look and act the same?
Anon25 [30]
The statement which explains why muscle cells and skin cells do not look and act the same is this: THE GENES IN EACH TYPE OF CELL ARE BEEN EXPRESSED DIFFERENTLY. 
All the cells in human's body has the same set of genes, this is because, all the cells in the body originated from a single fertilized egg. Even though all the cells in the body has the same origin, they are different from one another because, the cells use the same set of genes differently.
8 0
3 years ago
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A girl rides her scooter 5m North, 7m East, 5m South, and then 7m west. What is her displacement?
OlgaM077 [116]

Answer:

She is in the same place as she started. But she did move 28 units in total.

4 0
2 years ago
Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
IgorLugansk [536]

Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

4 0
3 years ago
NEED HELP ASAP PLEASE!
Tresset [83]

Answer:

7.false   8.commensalism  9.last one

Explanation:

6 0
3 years ago
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