Answer:
A parent with one copy of a dominant allele and one recessive coded Ww for the widow's peak is called heterozygous for a trait and has a 50 percent chance of passing on the dominant allele to each of his or her offspring, regardless of the gene inherited from the other parent.
Explanation:
hope this helps in some way sorry if it does not
Answer:
AO X BO
Explanation:
Offspring will look like AB AO BO OO
The answer to the question that is being presented above would be the phrase 'Mendel's law of inheritance'. <span>Family pedigrees are based on scientific evidence that is described by Mendel's law of inheritance. The other choices do not describe the statement better.</span>
<span>The answer is general senses. These are the senses which
are professed by reason of the receptors distributed all over the body such as temperature,
touch, and starvation, instead of knotted to a particular structure, like the
special senses - sight or hearing.</span>
Answer:
A. 21 rad/s
B. 200.5 rpm
C. 26.46 rad/s2
D. 0.299 Hz
Explanation:
Parameters given are:
Tangential velocity,v = 1.26m/s
Diameter (outer edge) = 0.120m
Outer edge radius, ro = 0.12/2
= 0.06m
A. Calculate Angular velocity
Angular velocity, w = v/r
= v/ro
= 1.26/0.06 = 21 rad/s
In rpm,
2pi/60 rad/s = 1 rpm
1 rad/s = 60/2pi rpm
Sp, 21 rad/s = 60 * 21/2pi rpm
= 200.5 rpm
B. Calculate the inner edge radius, ri given w = 500 rpm
Converting rpm to rad/s,
= 2pi/60 * 500 rad/s
= 52.34 rad/s
ri = v/w
= 1.26/ 52.36
= 0.024m
C. Calculating centripetal acceleration, a from the outer edge, ro
a = v2/r = w2r
= (1.26)2/0.06
= 26.46 rad/s
D. Calculate the frequency, f of the outer edge angular velocity, w = 21 rad/s
f = 2pi/w
= 2pi/21
= 0.299 Hz (or per second)
