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Mandarinka [93]
3 years ago
13

What is the radius and diameter?

Mathematics
2 answers:
arlik [135]3 years ago
6 0

Answer:

d=14 cm

r = 7 cm

Step-by-step explanation:

The diameter is 14 cm

The radius is 1/2 the diameter

r = d/2 = 14/2 = 7cm

MAXImum [283]3 years ago
4 0
Diameter = 14 cm, radius = 7 cm.
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Answer:

$85

Step-by-step explanation:

<u>Earning:</u>

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<u>Amount available for saving:</u>

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5 0
3 years ago
Read 2 more answers
? : 14 = 5 : 2 please solve this question- thank you!
babymother [125]

x/14 = 5/2

using cross product

2x =14*5

divide by 2

x = 14*5/2

x =35

5 0
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What's 5,250 divided by 6
ANTONII [103]
875

Use a calculator lol
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elect answers from the drop-down menus to correctly complete the statements. A scale factor of was applied to the first triangle
snow_tiger [21]
The scale factor is what u multiply the first image by to get the second image. So by dividing the second image by the first image will give u the scale factor.

6 / 1.5 = 4....so there is a scale factor of 4 because 1.5 * 4 = 6
7 0
3 years ago
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A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
3 years ago
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