ANSWER
2x-3=0
and
x+4=0
EXPLANATION
Given that:

Then to find roots of

is the same as finding the roots of

By the zero product property, we must have either,

Hence the equations that must be solved to find the roots are:
2x-3=0
and
x+4=0
1) <span>B)3x+6y=22
6x+12y=44
because the equations are equivalent to each other
2*(3x+6y=22) -----> 6x+12y=44
2) </span><span>5x+10y=15 should be multiplied by -2, to get 5x*(-2)=-10x, and x then can be eliminated
</span><span>A)-2</span>
Answer:
here
Step-by-step explanation:
15x-20x= -82+12=>
=> - 5x= -70=>
= x= 14
6 times 1 =6
2 times x =6
x=3
Answer:
250
Step-by-step explanation:
i think i might be wrong