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Hunter-Best [27]
3 years ago
11

Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a

nd the colors that appear face up on the first, second, and third rolls are recorded. (a) Find the probability of the event that exactly one of the colors that appears face up is red.
Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer:

12/27

Step-by-step explanation:

Step 1

We find all the total number of possible outcomes of rolling two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow.

Where

R = Red

B = Blue

Y = Yellow

RRR, BBB, YYY, RBY, RYB, YBR, YRB, BRY, BYR, BBY, BBR, YYB, RRY, RRB, BYB, BRB, YRY, YBY, RYR, RBR,YRR, BRR, RBB, RYY, BYY,YBB, YYR

We have 27 Total outcomes for this 6 faced die

Step 2

The event that exactly one of the colors that appears face up is red.

RBY, RYB, YBR, YRB, RBB, RYY, BBR,

BRB, BRY, YRY, BYR, YYR

Total number of Possible outcomes where EXACTLY one of the colours that appears face up is red = 12

The probability of the event that exactly one of the colors that appears face up is red = Number of possible outcomes/ Total number of outcomes

= 12/27

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