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Marrrta [24]
3 years ago
9

What are the solutions of this quadratic equation? x + 10 = 0

Mathematics
1 answer:
mars1129 [50]3 years ago
7 0
I think that the answer is d
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Bring the fraction a/a−4 to a denominator of 16−a^2<br><br> really do appreciate this thx
RSB [31]

Answer:

-a(a+4)/(16 - a²)

Step-by-step explanation:

            a/(a - 4)                  Multiply by (a + 4)/(a + 4)

= a(a + 4)/[(a – 4)(a + 4)]     Multiply the denominatorator terms

= a(a + 4)/(a² - 16)               Multiply by -1/(-1)

= -a(a+4)/(-a² + 16)              Reorder terms in denominator

= -a(a+4)/(16 - a²)

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Answer:nope

Step-by-step explanation: I wish

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246000 in scientific notation
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2.46 x 10⁵

Step-by-step explanation:

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Read 2 more answers
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
Please someone help with #14!!!
Marianna [84]
Which one do you need help with?
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3 years ago
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