Step-by-step explanation:
distance = -6-(-2) and 4-2
-6+2 and 2
-4 and 2 is distance
What you should do in this case is to use the following trinonometric relationship:
senx = C.O / h
Where
C.O: Opposite leg.
h: hypotenuse.
Substituting:
senx = (7) / (9)
Clearing x:
x = ASIN ((7) / (9))
x = 51.05755873
Answer:
The value of x is
x = 51 degrees.
It means that you have to find the solution of the systems of equations.
The measure of an angle formed by two tangent lines intersecting at a point outside the circle is equal to one-half their intercepted arcs.
XYZ = 1/2(XSZ - XZ)
XYZ = 1/2 (220 - 140)
XYZ = 1/2 (80)
XYZ = 40
The measure of angle XYZ is 40 degrees.
Hope this helps =)
There is some information missing in the question, since we need to know what the position function is. The whole problem should look like this:
Consider an athlete running a 40-m dash. The position of the athlete is given by
where d is the position in meters and t is the time elapsed, measured in seconds.
Compute the average velocity of the runner over the intervals:
(a) [1.95, 2.05]
(b) [1.995, 2.005]
(c) [1.9995, 2.0005]
(d) [2, 2.00001]
Answer
(a) 6.00041667m/s
(b) 6.00000417 m/s
(c) 6.00000004 m/s
(d) 6.00001 m/s
The instantaneous velocity of the athlete at t=2s is 6m/s
Step by step Explanation:
In order to find the average velocity on the given intervals, we will need to use the averate velocity formula:
so let's take the first interval:
(a) [1.95, 2.05]
we get that:
so:
(b) [1.995, 2.005]
we get that:
so:
(c) [1.9995, 2.0005]
we get that:
so:
(d) [2, 2.00001]
we get that:
so:
Since the closer the interval is to 2 the more it approaches to 6m/s, then the instantaneous velocity of the athlete at t=2s is 6m/s