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Phantasy [73]
3 years ago
5

Which of the following is not a type of bank?

Computers and Technology
2 answers:
pochemuha3 years ago
6 0
Payday seems like the answer to me!
andreyandreev [35.5K]3 years ago
3 0
Where is the following banks that is listed?
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Consider the following code segment.
mafiozo [28]

Answer:

for (int h = k; h >= 0; h--)

Explanation:

From the list of given options, option C answers the question.

In the outer loop

Initially, k = 0

In the inner loop,

h = k = 0

The value of h will be printed once because h>=0  means 0>=0 and this implies once

To the outer loop

k = 1

The inner loop will always assume value of k;

So,

h = 1

This will be printed twice because of the condition h>=0  means 1>=0.

Since 1 and 0 are >=0; 1 will be printed twice

To the outer loop

k = 2

The inner loop

h = 2

This will be printed thrice because of the condition h>=0  means 2>=0.

Since 2, 1 and 0 are >=0; 2 will be printed thrice

To the outer loop

k = 3

The inner loop

h = 3

This will be printed four times because of the condition h>=0  means 3>=0.

Since 3, 2, 1 and 0 are >=0; 3 will be printed four times

7 0
3 years ago
Write six causes of data lost
just olya [345]
<span>1. Deleting files accidentally
</span>

2. Viruses and damaging malware

3. Mechanical damages of hard drive

4. Power failures

5. Theft of computer

6. Spilling coffee, and other water damages

7. Fire accidents and explosions

<span>Hope this helps.</span>
3 0
3 years ago
1. If you purchase the renters insurance policy described above, you bring a suitcase of clothing and other general
Mazyrski [523]

Answer:

I think its c or d

Explanation:

hope this helps

7 0
3 years ago
Write a program that uses the function isPalindrome given in Example 6-6 (Palindrome). Test your program on the following string
Artist 52 [7]

Answer:

#include <bits/stdc++.h>

using namespace std;

bool isPalindrome(string str)

{

   char a,b;

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

   a=tolower(str[i]);//Converting both first characters to lowercase..

   b=tolower(str[length-1-i]);

   if (b != a )

return false;

}

return true;

   

}

int main() {

   string t1;

   cin>>t1;

   if(isPalindrome(t1))

   cout<<"The string is Palindrome"<<endl;

   else

   cout<<"The string is not Palindrome"<<endl;

return 0;

}

Output:-

Enter the string

madam

The string is Palindrome

Enter the string

abba

The string is Palindrome

Enter the string

22

The string is Palindrome

Enter the string

67876

The string is Palindrome

Enter the string

444244

The string is not Palindrome

Explanation:

To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.

6 0
2 years ago
There is a simple method for constructing a magic square for any odd value of n:
DaniilM [7]

Answer:

See Explaination

Explanation:

class MagicSquare():

def __init__(self,side):

self.side=side

self.two_dimension=[]

for row in range(1,side+1):

row_line=[]

for col in range(1,side+1):

row_line.append(0)

self.two_dimension.append(row_line)

def display(self):

row=0

col=int((self.side-1)/2)

for i in range(1,self.side**2+1):

self.two_dimension[row][col]=i

row-=1

col+=1

if row==-1:

row=self.side-1

if col==self.side:

col=0

if self.two_dimension[row][col]==0:

continue

else:

row+=1

if row==self.side:

row==0

for line in self.two_dimension:

for num in line:

print("{0:>3}".format(num),end=" ")

print()

def main():

for i in range(1,14,2):

square=MagicSquare(i)

square.display()

print("----------------------------------------------------")

if __name__ == '__main__':

main()

3 0
3 years ago
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