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Anna71 [15]
3 years ago
13

How do I solve this problem

Mathematics
1 answer:
quester [9]3 years ago
4 0
I think x equals 54


Hope this helps
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What is the approximate distance between the points (-3, -4) and (-8, 1) on a coordinate grid
tatyana61 [14]
\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -3 &,& -4~) 
%  (c,d)
&&(~ -8 &,& 1~)
\end{array}\\\\\\ %  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[-8-(-3)]^2+[1-(-4)]^2}\implies d=\sqrt{(-8+3)^2+(1+4)^2}
\\\\\\
d=\sqrt{25+25}\implies d=\sqrt{2\cdot 25}\implies d=\sqrt{2\cdot 5^2}\implies d=5\sqrt{2}
4 0
3 years ago
Read 2 more answers
How do you graph an explict equation
morpeh [17]
I think this might help but sorry if it does not but I hope it does :) :D - https://learnzillion.com/lesson_plans/5701-writing-an-explicit-formula-for-the-graph-of-an-exponential-relationship/
5 0
3 years ago
What is the solution to this systems of equation? 2x-3y=9 and 5x+3y=10​
mamaluj [8]

y = -5x/3 + 10/3

y = 2x/3 - 3

8 0
3 years ago
Explain how the value of the 7 in 327,902 will change if you move it to the tens place
-BARSIC- [3]
The tens place will be where the zero is which the value would be 70 since the 7 is in the thousand place the value is 7,000
7 0
3 years ago
Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
GREYUIT [131]

Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

6 0
3 years ago
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