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3 years ago

There are 5 green balls, 2 orange balls, 4 purple balls, and 1 pink ball in a bucket. You pick 1 ball from

Mathematics

1 answer:

bagirrra123 [75]3 years ago

8 0

B
The purple balls constitute 1/3 of the amount of balls there, so you’re that likely to pluck one out.

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hellppppp,mr. Raymond told students in a true-false quiz with 10 questions you are certain to get five correct if you just guess

Aleks [24]

Answer:

Step-by-step explanation:

Cause it just doesnt not making is sence

3 0

3 years ago

Line A is represented by the following equation:

Inga [223]

Line A : x + y = 2

The most likely equation for line B so that the set of equation has no solution is:

x + y = 4

====

x + y = 2
x = 2 - y

2-y + y = 4
0 = 4 - 2
0 ≠ 2

there is no value for x nor y. so, no solution.

5 0

3 years ago

Read 2 more answers

If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi

Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = $\mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2}$ --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and $\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}$

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

$\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16$

$34 \times 1+\frac{1}{2} \times a \times 1^{2}=18$

$34+\frac{a}{2}=18$

$\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}$

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

6 0

3 years ago

There were 230 shoppers at an electronics store on opening day. The specials that day allowed 21% of shoppers to receive a free

anastassius [24]

Answer:

a) About 48 of the shoppers, that is $230\frac{21}{100}$ of the shoppers, received a free set of earbuds.

b) About 58 shoppers, that is $\frac{230}{4}$ received $5 off their first purchase.

Step-by-step explanation:

a. About how many shoppers received a free set of earbuds?

21% out of 230. So

$230\frac{21}{100} = 2.3(21) = 48.3$

About 48 of the shoppers, that is $230\frac{21}{100}$ of the shoppers, received a free set of earbuds.

b. About how many shoppers received $5 off their first purchase?

25% out of 230, so:

$230\frac{25}{100} = 230\frac{1}{4} = \frac{230}{4} = 57.5$

About 58 shoppers, that is $\frac{230}{4}$ received $5 off their first purchase.

5 0

2 years ago

1 -1/3, 2 - 4/6, 1 - 3/9, 2 - 1/2 answer them all

Degger [83]

1-1/3=2/3
2-4/6=1 1/3
1-3/9=2/3
2-1/2=1 1/2

5 0

3 years ago

Read 2 more answers