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andreev551 [17]
3 years ago
5

How can you solve p2 - 12 =p ?

Mathematics
2 answers:
Andreas93 [3]3 years ago
4 0

- {p}^{2}  - 12 = p \\  {p}^{2}  - 12 - p = 0 \\   {p}^{2}  - p - 12 = 0

Now, use the mid term splitting technique

{p}^{2}  - 4p + 3p - 12 \\ =  p(p - 4) + 3(p - 4) \\  = (p + 3)(p - 4) \\  \\  \\  \\


From here
we'll do the same thing we do to find the zeroes,


p+3=0 or p -4 =0

p = -3 or p = 4

Therefore
p = -3 and 4



Licemer1 [7]3 years ago
3 0
P= 4 and -3
Move all the terms to the left side and set equal to zero. Then set each factor to zero.
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