<span>1. </span>The probability that one of the diners orders fish = number of diners who ordered fish / total number of diners
p1=45/100=0.45
<span>2. </span>The probability that one of the diners is wearing dress= number of diners wearing dress/ total number of diners
<span>3. </span>p2=14/100=0.14
<span>The probability that one of the diners ordered the fish or is wearing a dress is: p=0.45+0.14=0.59</span>
Y=4x-5... if you were asking for that in words
We are asked for the total or three card hands that can be made with two aces. The three-card hand should have two aces. We will use permutation in solving this problem and the solution is shown below:
nPr = n! /(n-r)!
n=3
r=2
3P2 = 3!/(3-2)!
3P2 = 6
The answer is 6.
Answer:
(If they were talking about 3,335, then) 100 times greater
(If they were talking about 3,335 then) 10 times greater
Step-by-step explanation:
When you visualize it, ignore the other numbers and think of only the threes.
Count how many spaces/places they are from each other, and that's how many 0s you should put after a 1 as your answer.
Same as decimal moving and multiplying by 10's.
Total cost, C = 8x^2 + 12xz
volume, V = (x^2)*z = 10
C = 8x^2 + 12x*10/x^2
= 8x^2 + 120/x
dC/dx = 16x - 120/x^2 = 0
16x = 120/x^2
x^3 = 120/16
x = 1.957 ft
d^2C/dx^2 = 16 +240/x^3 = +ve for x = 1.957
so, C is minimum when
x = 1.957 ft z = 2.61 ft
Length of the base x is 1.957 ft and height of side z is 2.61 ft
