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3 years ago

write a ratio for the following description: for every 6 cups of flour in a bread recipe there are two cups of milk

2 answers:

8 0

6:2 because there are 6 cups of flour and 2 cups of milk if u put the 2 first it means 2 cups to 6 cups and you need to answer it the exact way the it is asked I am in elementary school and I know this

NeX [460]3 years ago

5 0

Answer:

We can write as 6:2 or simplified as 3:1

Step-by-step explanation:

Ratio means writing in a fractional form where two things have a relationship.

Like here, it is given - for every 6 cups of flour in a bread recipe there are two cups of milk

There is a relation between the number of cups of flour and the number of cups of milk.

So, in ratio form we can write this as 6:2 or $\frac{6}{2}$

We can simplify also to 3:1 or $\frac{3}{1}$

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Answer:

Let the integers are p and q.

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10 + 88 = 98
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In case one of the integers is negative and one positive.

p < 0, q > 0

Use absolute value in this case.

Subtract the numbers and apply the sign of the number with the greater absolute value.

<u>Examples:</u>

- 10 + 15 = |15 - 10| = |5| = 5
- 15 + 10 = - |15 - 10| = - |5| = -5

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2 years ago

The coach needs 12 lbs of peanut butter to feed his football team. if he buys peanut butter in jars containing 1 1/4 lbs, how ma

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<span>The coach needs 12 lbs of peanut butter to feed his football team. if he buys peanut butter in jars containing 1 1/4 lbs, how many jars should he buy</span>

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3 years ago

Adam had 91 dollar. If he spent 21 dollars on new books, what is the ratio of money he still has to money he's spent?

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3. Answer- 13:3

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3 years ago

Read 2 more answers

Tyler ate x fruit snacks, Han ate 3/4 less than that. Write an equation to represent the relationship between the number Tyler a

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3 years ago

21. Who is closer to Cameron? Explain.

pickupchik [31]

Problem 21

<h3>Answer: Jamie is closer</h3>

-----------------------

Explanation:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)

To find out who's closer to Cameron, we need to compute the segment lengths AC and JC. Then we pick the smaller of the two lengths.

We use the distance formula to find each length

Let's find the length of AC.

$A = (x_1,y_1) = (20,35)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from A to C} = \text{length of segment AC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-65)^2 + (35-40)^2}\\\\d = \sqrt{(-45)^2 + (-5)^2}\\\\d = \sqrt{2025 + 25}\\\\d = \sqrt{2050}\\\\d \approx 45.2769257\\\\$

The distance from Arthur to Cameron is roughly 45.2769257 units.

Let's repeat this process to find the length of segment JC

$J = (x_1,y_1) = (45,20)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from J to C} = \text{length of segment JC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(45-65)^2 + (20-40)^2}\\\\d = \sqrt{(-20)^2 + (-20)^2}\\\\d = \sqrt{400 + 400}\\\\d = \sqrt{800}\\\\d \approx 28.2842712\\\\$

Going from Jamie to Cameron is roughly 28.2842712 units

We see that segment JC is shorter than AC. Therefore, Jamie is closer to Cameron.

=================================================

Problem 22

<h3>Answer: Arthur is closest to the ball</h3>

-----------------------

Explanation:

We have these key locations:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)
B = location of the ball = (35,60)

We'll do the same thing as we did in the previous problem. This time we need to compute the following lengths:

These segments represent the distances from a given player to the ball. Like before, the goal is to pick the smallest of these segments to find out who is the closest to the ball.

The steps are lengthy and more or less the same compared to the previous problem (just with different numbers of course). I'll show the steps on how to get the length of segment AB. I'll skip the other set of steps because there's only so much room allowed.

$A = (x_1,y_1) = (20,35)\\\\B = (x_2,y_2) = (35,60)\\\\d = \text{Distance from A to B} = \text{length of segment AB}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-35)^2 + (35-60)^2}\\\\d = \sqrt{(-15)^2 + (-25)^2}\\\\d = \sqrt{225 + 625}\\\\d = \sqrt{850}\\\\d \approx 29.1547595\\\\$

Segment AB is roughly 29.1547595 units.

If you repeated these steps, then you should get these other two approximate segment lengths:

JB = 41.2310563

CB = 36.0555128

-------------

So in summary, we have these approximate segment lengths

AB = 29.1547595
JB = 41.2310563
CB = 36.0555128

Segment AB is the smallest of the trio, which therefore means Arthur is closest to the ball.

3 0

3 years ago