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pav-90 [236]
3 years ago
7

Help me please !!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0
1:4 is you answer. 4-3 is 1 and you do the same to 7.
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7 0
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x + y = 42, xy = 108 then what is x and y. Is there any (non-quadratic)formula for finding this instead of the process of elimin
charle [14.2K]

Answer:

when x = 39.25, y = 2.75

when x = 2.75, x = 39.25

Step-by-step explanation:

use substitution method

x+y = 42 ------ (1)

xy = 108 ------ (2)

from (1) ,

x+y = 42

y = 42-x ------ (3)

substitute (3) into (2)

xy = 108

x( 42-x ) = 108

42x - x² = 108

-x² + 42x - 108 = 0

x² - 42x + 108 = 0

use the following formula to solve the value of x:

i) \: x =  \frac{ - b +   \sqrt{ {b}^{2} - 4ac } }{2a} \:  \\ ii) \: x =  \frac{ - b -  \sqrt{ {b}^{2} - 4ac }  }{2a}

a = 1

b = -42

c = 108

i) \: x =  \frac{ - b  +  \sqrt{ {b}^{2}  - 4ac} }{2a}

x =   \frac{ - ( - 42) +  \sqrt{( - 42) {}^{2}  - 4(1)(108)} }{2(1)}

x =  \frac{42 +  \sqrt{1764 - 432} }{2}

x  =  \frac{42 +  \sqrt{1332} }{2}

x =  \frac{42 + 6 \sqrt{37} }{2}

x = 21 + 3 \sqrt{37}

x = 39.25

ii) \: x \:  \frac{ - b -  \sqrt{ {b}^{2}  - 4ac} }{2a}

x =  \frac{ - ( - 42) -  \sqrt{( - 42) {}^{2}  - 4(1)(108} }{2(1)}

x =  \frac{42  -   \sqrt{1764 - 432} }{2}

x =  \frac{42 -  \sqrt{1332} }{2}

x =  \frac{42 - 6 \sqrt{37} }{2}

x = 21 - 3 \sqrt{37}

x = 2.75

the 2 values of x are x = 39.25 and x = 2.75

substitute x = 39.25 into (3)

y = 42-x

y = 42-39.25

y = 2.75

substitute x = 2.75 into (3)

y = 42-x

y = 42-2.75

y = 39.25

when x = 39.25, y = 2.75

when x = 2.75, x = 39.25

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The population of a town is 18,000 and is decreasing at a rate of 2% per year for six years
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