Which side lengths form a right triangle

Cookies are on sale! Today each cookie costs $0.75 less than the normal price. Right now if you buy 7 of them it will only cost

Talja [164]

Ok, let us use "C" as our variable that will equal the normal price.

(C - $.75) 7 = $2.80

Divide both sides of equation by 7
C - $.75 = $2.80 / 7 Add $.75 to both sides of equation

C = $.40 + $.75

C = $1.15

8 0

3 years ago

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In one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the enti

jekas [21]

Answer:

$X \sim Hyp (N = 810, M=102, n=4)$

$P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}$

And solving we got:

$P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583$

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

Step-by-step explanation:

For this case we can model the variable of interest with the hypergeometric distribution. And with the info given we can do this:

$X \sim Hyp (N = 810, M=102, n=4)$

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

And for this case we want to find the probability that none of the scales selected would be defective so we want to find this:

$P(X=0)$

And using the probability mass function we got:

$P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}$

And solving we got:

$P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583$

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

6 0

3 years ago

Answer ALL questions if u cant see all the answers its fine all u need is the question

photoshop1234 [79]

For the triangle question, it should probably be A. Sorry if it's wrong.

8 0

4 years ago

While shopping for clothes, Curtis spent $44 less than 3 times what Jaclyn spent. Curtis

Vaselesa [24]

Just multiply 44 times 3 the you should get your answer

3 0

3 years ago

Linda walked 3/4 of the length of the Tremont Trail before stopping for a rest. How far had Linda walked on the trail? Tremont T

Afina-wow [57]

Answer:

2 5/8 miles or 2.625 miles

Step-by-step explanation:

We are told in the question that

Linda walked 3/4 of the length of the Tremont Trail before stopping for a rest.

From the question, the length of the Tremont Trail = 3 1/2 miles

Hence, the distance (how far )Linda has walked =

3/4 of 3 1/2 miles

= 3/4 × 3 1/2 miles

= 3/4 × 7/2 miles

= 21/8 miles

= 2 5/8 miles or 2.625 miles

Therefore, Linda had walked 2 5/8 miles or 2.625 miles on the Tremont trail

3 0

4 years ago

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