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Vikentia [17]
3 years ago
12

The disk enclosed by the circle x+y = 4 is revoived about the y-axis to generate solid sphere. A hele of diameter 2 units is the

n bored through the sphere along the y-axis. Find the voliime of the cored sphere​
Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Step-by-step explanation:

Suppose we have a curve, y = f(x).

y = f(x)

x = a x = b

Imagine that the part of the curve between the ordinates x = a and x = b is rotated about the

x-axis through 360◦

. The curve would then map out the surface of a solid as it rotated. Such

solids are called solids of revolution. Thus if the curve was a circle, we would obtain the surface

of a sphere. If the curve was a straight line through the origin, we would obtain the surface of

a cone. Now we already know what the formulae for the volumes of a sphere and a cone are,

but where did they come from? How can they calculated? If we could find a general method

for calculating the volumes of the solids of revolution then we would be able to calculate, for

example, the volume of a sphere and the volume of a cone, as well as the volumes of more

complex solids.

To see how to carry out these calculations we look first at the curve, together with the solid it

maps out when rotated through 360◦

.

y = f(x)

Now if we take a cross-section of the solid, parallel to the y-axis, this cross-section will be a

circle. But rather than take a cross-section, let us take a thin disc of thickness δx, with the face

of the disc nearest the y-axis at a distance x from the origin.

www.mathcentre.ac.uk 2

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5 0
2 years ago
Hello, how can I do this equation?
kompoz [17]
(9^x) - 3 = 2*3^x
(9^x) - 3 - (2*3^x) = (2*3^x) - (2*3^x)
(9^x) - (2*3^x) - 3 = 0
(3^2)^x - 2*(3^x) - 3 = 0
3^(2x) - 2*(3^x) - 3 = 0
3^(x*2) - 2*(3^x) - 3 = 0
(3^x)^2 - 2*(3^x) - 3 = 0
z^2 - 2*z - 3 = 0  ............ let z = 3^x
(z - 3)(z + 1) = 0

If z-3 = 0, then z = 3 when we isolate z
If z = 3, and z = 3^x, then
z = 3
3^x = 3
3^x = 3^1
x = 1
which is a solutin in terms of x

If z+1 = 0 then z = -1
If z = -1 and z = 3^x, then there are NO solutions for this part of the equation
The quantity 3^x is never negative no matter what the x value is

---------------------------------------------------------------

Answer: x = 1
4 0
3 years ago
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