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Olenka [21]
3 years ago
5

What are the answers?

Mathematics
2 answers:
Travka [436]3 years ago
4 0

Answer:

Pentagon is 8

Square is 12

last question is 36

Step-by-step explanation:

if we know that circle is 7, subtract that from 27. You now have 20. So take out the circle in the second problem.

<u>Pentagon</u> + Square = 20 .

<u>Pentagon</u> +<u>Pentagon</u> + Sqaure =28. Adding a Pentagon to the third problem makes it go from 20 to 28. Looking at the second problem you know that 8 + Square = 20. Subtract 8 from 20. You now have 12.

Square = 12.

const2013 [10]3 years ago
3 0

Answer:

Circle = 7

Pentagon = 8

Square = 12

Square + Square + Square = 36

Step-by-step explanation:

Since you know the circle is 7, the square plus the pentagon must be 20. That means the pentagon in the third equation is 8. This means the square is 12.

So, 12 + 12 + 12 = 36.

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A population of geese grow in such a way that each generation is simply 2.2 times the previous generation. There were 3 geese in
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Read 2 more answers
What is the geometric mean of the pair of numbers? 245 and 5
VLD [36.1K]

Answer:

35

Step-by-step explanation:

The geometric mean of n numbers is the n-th root of their product.

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7 0
3 years ago
The chance of an IRS audit for a tax return with over $25,000 in income is about 2% per year. We are interested in the expected
Dominik [7]

Answer:

The probability that a person is audited more than twice is 0.0037 .

Step-by-step explanation:

We are given that The chance of an IRS audit for a tax return with over $25,000 in income is about 2% per year.

We are interested in the expected number of audits a person with that income has in a 16-year period

Now we are supposed to find the probability that a person is audited more than twice.

So, We will use binomial distribution

So, Probability of success =p= 2% = 0.02

So, Probability of failure = q=1-0.02=0.98

n = 16

Now we are supposed to find the probability that a person is audited more than twice i.e. P(x \geq 2)

So, P(x \geq 2)= 1-(P(x=0)+P(x=1)+P(x=2)

Formula :^nC_x p^x q^{n-x}

So,P(x \geq 2)= 1-(^{16}C_0 {(0.02)}^0 {(0.98)}^{16-0}+^{16}C_1 {(0.02)}^1 {(0.98)}^{16-1}+ ^{16}C_2 {(0.02)}^2 {(0.98)}^{16-2})P(x \geq 2)= 1-(\frac{16!}{0!(16-0)!} {(0.02)}^0 {(0.98)}^{16-0}+\frac{16!}{1!(16-1)!} {(0.02)}^1 {(0.98)}^{16-1}+\frac{16!}{2!(16-2)!} {(0.02)}^2 {(0.98)}^{16-2})

P(x \geq 2)= 1-(0.9963)

P(x \geq 2)= 0.0037

Hence the probability that a person is audited more than twice is 0.0037 .

8 0
4 years ago
Please I need a lot can someone help
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Use the substitution method

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