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Brrunno [24]
3 years ago
7

PLEASE HELP!!!! The problem is in the photo below.

Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

A is correct.

Step-by-step explanation:

Here, the x would represent the gallons per minute. The minutes are unknown, so it's just a variable. It can't be B either, because the addition sign would mean that the pool is being filled instead of drained.

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Original amount: 27<br> End amount: 38.61<br><br> Increase or decrease
vichka [17]

Answer:

increase

Step-by-step explanation:

11.61 was added to 27

5 0
3 years ago
Find the product of 400 and 9.460730473 times 10/15
azamat

Answer:

272.973820315

Step-by-step explanation:

5 0
3 years ago
The median is often a better representative of the central value of a data set when the data set: source is bimodal. has a high
Lorico [155]
The median is a better representative of the central value of a data set when
the data set is highly skewed.

Note that
The median and average value only coincide when the distribution is perfectly normal.
Many outliers will also skew the distribution, and the median becomes a better representative.
8 0
3 years ago
To find the standard deviation of the diameter of wooden​ dowels, the manufacturer measures 19 randomly selected dowels and find
loris [4]

Answer:

Option D -  [0.12

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The​ 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of \chi^2 is UC=\chi(\frac{0.05}{2},18) = 31.5264

Lower critical value of \chi^2 is  

LC=\chi(1-\frac{0.05}{2},18) = 8.2307

Lower limit of the 95% confidence interval for the population variance

L=\frac{(df)\times (s^2)}{UC}

L=\frac{18\times (0.16^2)}{31.5264}

L=\frac{18\times0.0256}{31.5264}

L=\frac{0.4608}{31.5264}

L=0.0146

Upper limit of the 95% confidence interval for the population variance

U=\frac{(df)\times(s^2)}{LC}

U=\frac{18\times (0.16^2)}{8.2307}

U=\frac{18\times0.0256}{8.2307}

U=\frac{0.4608}{8.2307}

U=0.0559

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

[\sqrt{0.0146}

[0.1208

or  [0.12

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is  [0.12

6 0
3 years ago
Solve the system of equations of equations by graphing on your calculator rounded to 3 decimal spaces
ozzi

Answer:

1 and 1/2 x2 =3

Step-by-step explanation:

3 0
3 years ago
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