Does Y=3/X represent a linear function when X=0

1 answer:

8 0

Hello,

Divide by 0 is impossible.
So when x=0; y is undefined.

<span>Therefore, y cannot be a linear function.</span>

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1/(x+4)(x-2)(x-5) excluded values

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Answer:

see explanation

Step-by-step explanation:

The excluded values are any values of x that make the function undefined

Given

$\frac{1}{(x+4)(x-2)(x-5)}$

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.

(x + 4)(x - 2)(x - 5) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

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x = - 4, x = 2, x = 5 are the excluded values

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