Answer:
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
Step-by-step explanation:
We have three conditions
(1) 5P = 3S
(2) S = C + 0.30
(3) P = C – 0.20 Substitute (3) into (1)
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(4) 5(C – 0.20) = 3S Substitute (2) into (4)
5(C – 0.20) = 3(C + 0.30) Remove parentheses
5C – 1.00 = 3C + 0.90 Add 1.00 to each side
5C = 3C + 1.90 Subtract 3C from each side
2C = 1.90 Divide each side by 2
C = $0.95 Substitute C into Equation (2)
=====
S = 0.95 + 0.30
S = $1.25 Substitute C into Equation (3)
=====
P = 0.95 – 0.20
P = $0.75
1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25
Answer: X = 7
Step-by-step explanation:
Or, you don't have to plug any of those in and solve for x
subtract 6 from both sides
2x = 14
divide 14 by 2x
x=7
Answer:
what grade you in do you even do your work this easy is b
72+28+66+81=297
360-297=63
She would need to score 63 on her last exam.
Answer:
28 short-sleeved shirts were sold and 23 long-sleeved shirts were sold.
Step-by-step explanation:
We can solve this question by a system of equations.
I am going to say that:
x is the number of short-sleeved shirts sold.
y is the number of long-sleeved shirts sold.
A department store sold 51 shirts one day.
This means that
All short-sleeved shirts cost $14.00 each and all long-sleeved shirts cost $23.00 each. Total receipts for the day were $921.00.
This means that
How many of each kind of shirt were sold?
We have to solve the system of equations.
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28 short-sleeved shirts were sold and 23 long-sleeved shirts were sold.