Answer:
Therefore Perimeter of Rectangle ABCD is 4 units
Step-by-step explanation:
Given:
ABCD is a Rectangle.
A(-6,-4),
B(-4,-4),
C(-4,-2), and
D (-6,-2).
To Find :
Perimeter of Rectangle = ?
Solution:
Perimeter of Rectangle is given as
![\textrm{Perimeter of Rectangle}=2(Length+Width)](https://tex.z-dn.net/?f=%5Ctextrm%7BPerimeter%20of%20Rectangle%7D%3D2%28Length%2BWidth%29)
Length = AB
Width = BC
Now By Distance Formula we have'
![l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}](https://tex.z-dn.net/?f=l%28AB%29%20%3D%20%5Csqrt%7B%28%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%20%29%7D)
Substituting the values we get
![l(AB) = \sqrt{((-4-(-6))^{2}+(-4-(-4))^{2} )}](https://tex.z-dn.net/?f=l%28AB%29%20%3D%20%5Csqrt%7B%28%28-4-%28-6%29%29%5E%7B2%7D%2B%28-4-%28-4%29%29%5E%7B2%7D%20%29%7D)
![l(AB) = \sqrt{((2)^{2}+(0)^{2} )}=2\ unit](https://tex.z-dn.net/?f=l%28AB%29%20%3D%20%5Csqrt%7B%28%282%29%5E%7B2%7D%2B%280%29%5E%7B2%7D%20%29%7D%3D2%5C%20unit)
Similarly
![l(BC) = \sqrt{((-4-(-4))^{2}+(-2-(-4))^{2} )}](https://tex.z-dn.net/?f=l%28BC%29%20%3D%20%5Csqrt%7B%28%28-4-%28-4%29%29%5E%7B2%7D%2B%28-2-%28-4%29%29%5E%7B2%7D%20%29%7D)
![l(BC) = \sqrt{((0)^{2}+(2)^{2} )}=2\ unit](https://tex.z-dn.net/?f=l%28BC%29%20%3D%20%5Csqrt%7B%28%280%29%5E%7B2%7D%2B%282%29%5E%7B2%7D%20%29%7D%3D2%5C%20unit)
Therefore now
Length = AB = 2 unit
Width = BC = 2 unit
Substituting the values in Perimeter we get
![\textrm{Perimeter of Rectangle}=2(2+2)=2(4)=8\ unit](https://tex.z-dn.net/?f=%5Ctextrm%7BPerimeter%20of%20Rectangle%7D%3D2%282%2B2%29%3D2%284%29%3D8%5C%20unit)
Therefore Perimeter of Rectangle ABCD is 4 units
Answer:
4. P=32 A=64 and 3 is just complicated sorry
Step-by-step explanation:
s is the length and w is width which the equation is 2s+2w=P
Answer:
2/5 of 3 = 2/5 * 3 = 6/5....what he plants
(6/5) / 5 = 6/5 * 1/5 = 6/25 <== what each friend got
Step-by-step explanation:
Step-by-step explanation:
The correct answer is 5i![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)