49.491 millimeters of acid is present
<em><u>Solution:</u></em>
Given that, chemist is using 351 milliliters of a solution of acid and water
14.1% of the solution is acid
To find: Milliliters of acid present
From given statement,
Solution of acid and water = 351 ml
14.1% of the solution is acid, which means that 14.1 % of 351 ml is acid
Therefore,
Milliliters of acid present = 14.1 % of 351 ml
Here "of" means multiplication
Therefore,


Thus 49.491 millimeters of acid is present
Whenever you want to write the equation of a parallel line through some point (h, k), you can ...
- remove any added constant in the original given equation
- replace x with (x-h)
- replace y with (y-k)
- rearrange the resulting equation to the form required by the problem.
Using this formula here, we get
... 2(y +5) = 3(x -2)
Your answer form requires you solve this for y.
... 2y + 10 = 3x -6 . . . . . eliminate parentheses
... 2y = 3x -16 . . . . . . . . subtract the constant on the left (10)
... y = (3/2)x -8 . . . . . . divide by 2
6 groups of 3 6 times 3 which equals 18
and 18 divided by 4 is 4.5 so it takes 5 cars.
3/4 is 0.75.
33/40 is 0.825.
So 3/4 is less than 0.825.