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3 years ago

How much is 2/3 of 9 marbles?

Mathematics

1 answer:

Umnica [9.8K]3 years ago

4 0

( 9 ÷ 3 ) x 2 = 3 x 2 = 6 marbles ;

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A magazine publisher is informed that 72% of subscribers last year did not renew their subscriptions. This publisher wants to ra

aliya0001 [1]

Answer:

Sampling frame

Explanation:

A sampling frame is the source where the researcher draws his samples from. In other words, a sampling frame is like the population where the researcher gets samples for his investigation. In the above example, we are told the researcher wants to know why the 72% that subscribed last year didn't subscribe this year. He draws a sample of 8% from the 72% that he is trying to study, therefore the 72% are the sampling frame from where he gets his sample.

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3 years ago

Will mark brainliest Find the sum of x^2 + 3x and -2x^2 + 9x +5.

zimovet [89]

Answer: -x^2 + 12x +5

Step-by-step explanation:

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3 years ago

Please help with this question

amid [387]

Answer:

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Step-by-step explanation:

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3 years ago

Please help will give brainliest!! Just define the variables and write the two equations for the two problems you don't have to

LenKa [72]

Answer:

lets say 4 is a and 2 is b.

Step-by-step explanation:

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This case will give you 52 dollars % tax

yw :)

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2 years ago

Read 2 more answers

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

lubasha [3.4K]

First find a parameterization for the curve of intersection.

Given the equation of a cylinder, a natural choice for a parameterization would be one utilizing cylindrical coordinates. Here,

$16x^2+y^2=16\implies x^2+\left(\dfrac y4\right)^2=1$

which suggests we could use

$\begin{cases}x(t)=\cos t\\y(t)=4\sin t\\z(t)\end{cases}$

with $0\le t\le2\pi$ , and we get $z(t)$ from the equation of the plane,

$x+y+z=12\implies z(t)=12-x(t)-y(t)=12-\cos t-4\sin t$

Now use the arc length formula:

$\displaystyle\ell=\int_0^{2\pi}\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$

$\displaystyle\ell=\int_0^{2\pi}\sqrt{\sin^2t+16\cos^2t+(\sin t-4\cos t)^2}\,\mathrm dt$

$\displaystyle\ell=\sqrt2\int_0^{2\pi}\sqrt{\sin^2t-4\cos t\sin t+16\cos^2t}\,\mathrm dt\approx\boxed{24.0878}$

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4 years ago