Question

If LaTeX: \frac{12x^2-6x}{3}=ax^2+bx+c,12 x 2 − 6 x 3 = a x 2 + b x + c , what is the value of LaTeX: aa?

Answer 1

Answer:

$a=4$

Step-by-step explanation:

Given the expression

$\frac{12x^2-6x}{3}=ax^2+bx+c$

Simplifying the left hand side

$\dfrac{12x^2-6x}{3}=\dfrac{12x^2}{3}-\dfrac{6x}{3}=4x^2-2x$

Comparing our result with the right hand side

$4x^2-2x=ax^2+bx+c\\4x^2=ax^2\\a=4$

The value of a is 4.