All categories

3 years ago

Pb is a line segment on a number line. It has endpoints at -2 and 12. What is the coordinate of its midpoint? show your work

Mathematics

1 answer:

stiks02 [169]3 years ago

7 0

Answer:

The midpoint is 5

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two numbers is equal to

$M=(\frac{x1+x2}{2})$

we have

The endpoints at -2 and 12

substitute the values in the formula

$M=(\frac{-2+12}{2})$

$M=(5)$

therefore

The midpoint is 5

You might be interested in

9x+11y=-14<br> 6x-5y=-34<br> Resolver por regla de cramer

Marizza181 [45]

Answer:

x=-4 y=2

Step-by-step explanation:

y=-14-9x÷9

6x-5 (14-9x÷9)=-34

6x-(70+45x÷9)=-34

Take LCM

and then do it

3 0

3 years ago

Work out the mean for the data set below: 6, 4

aliina [53]

Answer:

Step-by-step explanation:

The mean is the same as the average value of a data set and is found using a calculation. Add up all of the numbers and divide by the number of numbers in the data set.

8 0

4 years ago

Please help asap!!!!!!!

valkas [14]

Answer:

So the answer is A

Step-by-step explanation:

$f(x)=815.03(1.38)^{x}$

f(1) = 1124.74

f(2)= 1552.143

f(3) = 2141.9575

f(4)= 2955.901

f(5)= 4079.1439

So the answer is A

$f(x)=1.38x^{2} -2.64x+815.03$

f(1) = 813.77

wrong!

$f(x)= 1.38x+815.03$

f(1) = 816.14

$f(x)=815.03\sqrt{x} -1.38$

f(1)= 813.65

wrong!

8 0

3 years ago

Jasmine's pet guinea pig gained 8 ounces in one month. Write an integer to describe the amount of weight her pet gained.

quester [9]

X+8=(weight) could I get a brainliest

3 0

3 years ago

X^2 + 4x - 9 = (x + a)^2 + b<br><br> Find the value of a and the value of b

REY [17]

Answer:

Step-by-step explanation:

We have three ways.

$(a+b)^2=a^2+2ab+b^2\qquad(*)$

$\bold{1.}\\\\x^2+4x-9=x^2+2(x)(2)-9=\underbrace{x^2+2(x)(2)+2^2}_{(*)}-2^2-9\\\\=(x+2)^2-4-9=(x+2)^2-13\\\\x^2+4x-9=(x+a)^2+b\\\Downarrow\\(x+2)^2-13=(x+a)^2+b\Rightarrow \boxed{\bold{a=2, b=-13}}$

$\bold{2.}\\\\\underbrace{(x+a)^2}_{(*)}+b=x^2+2ax+a^2+b\\\\x^2+4x-9=x^2+2ax+(a^2+b)\Rightarrow 4=2a\ \text{and}\ -9=a^2+b\\\\4=2a\qquad\text{divide both sides by 2}\\\\\dfrac{4}{2}=\dfrac{2a}{2}\\\\2=a\to \boxed{\bold{a=2}}\\\\\text{Substitute to the second equation:}\\\\-9=2^2+b\\\\-9=4+b\qquad\text{subtract 4 from both sides}\\\\-9-4=4-4+b\\\\-13=b\to \boxed{\bold{b=-13}}$

$\bold{3.}\\\\(x+a)^2+b-\text{it's a vertex form of an equation of a parabola}\\\\\text{Let}\ y=a(x-h)^2+k\ -\ \text{the euation of a parabola}\ y=ax^2+bx+c.\\\\\text{Then}\ h=\dfrac{-b}{2a},\ k=\dfrac{-(b^2-4ac)}{4a}\\\\x^2+4x-9\to a=1,\ b=4,\ c=-9\\\\h=\dfrac{-4}{2(1)}=\dfrac{-4}{2}=-2\\\\k=\dfrac{-(4^2-4(1)(-9))}{4(1)}=\dfrac{-(16+36)}{4}=\dfrac{-42}{4}=-13\\\\\text{Therefore}\\\\x^2+4x-9=(x+a)^2+b\\\\(x-(-2))^2+(-13)=(x+a)^2+b\\\\(x+2)^2-13=(x+a)^2+b\to\boxed{\bold{a=2,\ b=-13}}$

4 0

3 years ago