Question

How to do 7z2 5z4 d3 d8

Answer 1

Answer:

$35{z}^{6} \cdot \: {d}^{11}$

Step-by-step explanation:

Let us assume , we want to find the product of

$7 {z}^{2} \cdot \: 5 {z}^{4} \cdot \: {d}^{3} \cdot \: {d}^{8}$

We rewrite as:

$7 \times 5{z}^{2} \cdot \: {z}^{4} \cdot \: {d}^{3} \cdot \: {d}^{8}$

We multiply coefficients and apply the product rule of exponents.

According to the product rule, when the base is the same for a product, we write one base and add the exponents.

$35{z}^{2 + 4} \cdot \: {d}^{3 + 8}$

We simplify the exponents to get;

$35{z}^{6} \cdot \: {d}^{11}$