(2x+4) +(3x-1) +(x+1)=34
6x+4=34
x=5
AB=14, BC=14, AC=6
The amount of different combos possible would be 165 // Hope this helped, comment below for any clarifications // Brainliest ;) Thanks!! //
Answer:
false, false, true, true, true
Step-by-step explanation:
Let's check each of the answers by plugging them into the inequality.
-2 (false):
which is false.
-1 (false):
which is false.
0 (true):
which is true.
1 (true):
which is true.
2 (true):
which is true.
Answer:
see below
Step-by-step explanation:
x^-2 = 1/x^2 Let x = -2 1/ (-2)^2 = 1/4
x^-1 = 1/x^1 Let x = -2 1/ (-2)^1 = 1/(-2) = -1/2
x^0 = 1
x^1 = x Let x = -2 (-2)
x^2 = Let x = -2 (-2)^2 = 4
1:(12,14)
2: 3
3:(15,30)
4: 6
5(8,12)
6:5
7:(35,42)
8:;
