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3 years ago

WORTH 25 POINTS PLEASE HELP!!!

2 answers:

7 0

Just subtract the smaller volume from the larger:

10 × 10 ×15 - 7 × 9 × 12

First you would multiply 10 × 10 × 15 = 1500 and then multiply 7 × 9 × 12 = 756.

After you would subtract 1500 - 756 which would give you 744

I hope that helped!

polet [3.4K]3 years ago

5 0

Step-by-step explanation:

First You Find The Volume for Both Boxes. Then You Subtract Them!

You might be interested in

Consider the following data: x −4−4 −3−3 −2−2 −1−1 00 P(X=x)P(X=x) 0.20.2 0.30.3 0.10.1 0.20.2 0.20.2 Copy Data Step 4 of 5 : Fi

AysviL [449]

Answer:

$P(x\geq -1) = 0.4$

Step-by-step explanation:

We are given the following in the question:

x: −4 −3 −2 −1 0

P(X=x): 0.2 0.3 0.1 0.2 0.2

We have to evaluate

$P(x\geq -1)$

Since it is a discrete probability distribution as

$\displaystyle\sum P(X=x_i) = 0.2 + 0.3 + 0.1 + 0.2 + 0.2 = 1$

We can evaluate the probability as:

$P(x\geq -1) = P(x = -1 + P(x = 0)\\P(x\geq -1) = 0.2 + 0.2\\P(x\geq -1) = 0.4$

Thus, 0.4 is the require probability.

4 0

3 years ago

Can some help me out with this EXTRA POINTS!!

Butoxors [25]

Answer: ≈ 185.73009

Step-by-step explanation:

area of square: $length^{2}$

area of circle: $\frac{radius^{2} * \pi }{y}$

length: 15

radius = diameter/2

radius: 5

area of square - area of circle = area between square and circle:

$15^{2} - \frac{5^{2} * \pi }{2} = 225 - \frac{25\pi}{2}$ ≈ 185.73009

hope it helps!

Please mark as brainliest.

8 0

2 years ago

Hello please help thanks i’ll give brainliest!

erastovalidia [21]

Answer: A

Step-by-step explanation: Hope this help :D

8 0

3 years ago

Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

djverab [1.8K]

$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$

$\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM$

Hence there is no such natural numbers exist.

7 0

3 years ago

Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili

pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0

2 years ago