The approximation of the slope of the graph at t = 10 days using this secant lines are 11750 and -11750, respectively.
<h3>How to determine the slope of the secant lines?</h3><u>(a) t = 10 days and a day earlier</u>
This means that:
t = 10 and t = 9
The function is given as:
Calculate N(10)
Evaluate
N(10) = 100000
Next, calculate N(9)
Evaluate
N(9) = 88249.6902585
The slope is then calculated using"
This gives
Evaluate
m = 11750.3097415
Approximate
m = 11750
<u>(b) t = 10 days and a day later</u>
This means that:
t = 10 and t = 100
The function is given as:
In (a), we have:
N(10) = 100000
Next, calculate N(11)
Evaluate
N(11) = 88249.6902585
The slope is then calculated using:
This gives
Evaluate
m = -11750.3097415
Approximate
m = -11750
Hence, the approximation of the slope of the graph at t = 10 days using this secant lines are 11750 and -11750, respectively.
Read more about secant lines at:
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