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WITCHER [35]
2 years ago
8

Subtract (6k+2)-(3k-2)

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
6 0

3k+4 is the answer. Hope this helps

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Given that these simultaneous equations
Tatiana [17]

The value of k is(3\sqrt{ 10})/2

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= \sqrt{15-2x^2}...........(eq iii)

Substitute the value of y into eq i

x-(\sqrt{15-2x^2}= k

x- (\sqrt{15} - 2x= k

k= (3\sqrt{ 10})/2

Read more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

3 0
1 year ago
Multiplication Property of Equality---- If 6x divided by 8 = 40, then______
NNADVOKAT [17]

Answer:

Option C.) 6x=320

Step-by-step explanation:

we know that

The <u>Multiplication Property of Equality</u> states that if you multiply both sides of an equation by the same number, the sides remain equal

we have

\frac{6x}{8}=40

Apply the multiplication property of equality

Multiply by 8 both sides

\frac{6x}{8}(8)=40(8)

6x=320

therefore

The answer is the Option C

6 0
3 years ago
Read 2 more answers
How do you solve and simplify
DedPeter [7]
F(x) = 1/(x+2)   & g(x) = x/(x-3)


(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:

1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)

7 0
2 years ago
I needdd helpp :)))))
NeTakaya
I can’t see the scenario on top so can’t rlly help u out sorry
3 0
2 years ago
Jess works in a store that sells toys.He earns 4% as his commissions for the sales that amounts above Nu 10,000.In one of the mo
Levart [38]

it's 400

hope this helps

7 0
2 years ago
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