The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y=
...........(eq iii)
Substitute the value of y into eq i
x-(
= k
x- (
= k
k= 
Read more about simultaneous equations here:
brainly.com/question/16863577
#SPJ1
Answer:
Option C.) 6x=320
Step-by-step explanation:
we know that
The <u>Multiplication Property of Equality</u> states that if you multiply both sides of an equation by the same number, the sides remain equal
we have

Apply the multiplication property of equality
Multiply by 8 both sides


therefore
The answer is the Option C
F(x) = 1/(x+2) & g(x) = x/(x-3)
(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:
1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)
I can’t see the scenario on top so can’t rlly help u out sorry