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riadik2000 [5.3K]
3 years ago
11

Standred from and word from

Mathematics
2 answers:
Komok [63]3 years ago
5 0
Thirty-two million, five thousand and 8. you can not put the number in standard form because the number is already in standard form.
Orlov [11]3 years ago
4 0
Thrirty-two million,five thousand,and eight.
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Consider the radical equation √n+ 4 = n-2.
muminat

Answer:

Pretty sure neither of them work. So prolly the last one. Hope I’m right :)

3 0
3 years ago
when a measurement in inches is converted to centimeters, will the number of centimeters be greater or less than the number of i
Margarita [4]
Greater because a centimeter is smaller than an inch.
4 0
3 years ago
What is the slope of the line that passes through the points (1,7) and (3,1)
Vera_Pavlovna [14]
1-7/3-1
-6/2
-3
Therefore, the slope of the line that passes through these points is -3.
3 0
3 years ago
Read 2 more answers
Find the equation of the circle that has a diameter with endpoints located at (7, 3) and (7, –5).
posledela
So hmm check the picture below, that's about the circle and the endpoints, but notice, the endpoints make up a segment, namely the diameter of the circle, well.... let's see how long that is, because, the radius is half the diameter

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 7}}\quad ,&{{ 3}})\quad 
%  (c,d)
&({{ 7}}\quad ,&{{ -5}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{(7-7)^2+(-5-3)^2}\implies d=\sqrt{0+(-8)^2}\implies d=8
\\\\\\
\textit{the radius is half that, so is }\boxed{r=4}

now.. hmmm notice, the midpoint of the diameter, is the center of the circle, let's check that one out

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 7}}\quad ,&{{ 3}})\quad 
%  (c,d)
&({{ 7}}\quad ,&{{ -5}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ 7+7}}}{2}\quad ,\quad \cfrac{{{ -5}} + {{ 3}}}{2} \right)\implies \left( \cfrac{14}{2}\ ,\ \cfrac{-2}{2} \right)\implies \boxed{(7,-1)}

now.. that we know what the center is, and what the radius is, well

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k\quad }})\qquad 
radius=&{{ r}}\\
&7&-1&4
\end{array}

5 0
3 years ago
Matt walks his dog around the block. The block has a rectangle shape. The dimensions of the block is 3 miles long and 2450 yards
padilas [110]
So first we need to convert all of these to feet:

2450 yards is 7350 feet
3 miles is 15840 feet

Now we need to find the perimeter and then multiply by 2:

2(7350) + 2(15840) = 43680
2(43680) = 87360

7 0
3 years ago
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