#include
int main()
{
int num;
scanf("%d", &num);
printf("%d", num*num);
return 0;
}
4+1, 3+2, 2+3, 1+4. 4 total combinations, unless 4+1 and 1+4 are the same. In that case, there are only 2, 1+4, and 2+3
Answer:
y=-2/3x-3
Explanation
Answer:
Problem:
Solve 3x−y=6;y=x−4
Steps:
I will try to solve your system of equations.
y=x−4;3x−y=6
Step: Solvey=x−4for y:
Step: Substitutex−4foryin3x−y=6:
3x−y=6
3x−(x−4)=6
2x+4=6(Simplify both sides of the equation)
2x+4+−4=6+−4(Add -4 to both sides)
2x=2
2x
2
=
2
2
(Divide both sides by 2)
x=1
Step: Substitute1forxiny=x−4:
y=x−4
y=1−4
y=−3(Simplify both sides of the equation)
Answer:
y=−3 and x=1
Step-by-step explanation:
Hope this helped you
