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Svetlanka [38]
2 years ago
11

Round each decimal 32.62 tenths place

Mathematics
1 answer:
Tresset [83]2 years ago
3 0

Answer:

32.6

Step-by-step explanation:

Look at the decimal in the hundredths place in 32.62

If the number is 0-4, round down. If the number is 5-9, round up.

In 32.62, the number in the hundredths place is 2. So, we round down to 32.6

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The answer to the question

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2 years ago
(-5)^2-2x(-9)+6<br> Please show work and step by step.
Varvara68 [4.7K]

Answer:

<h2>49</h2>

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

==============================================

(-5)² - 2 × (-9) + 6          <em>first </em><em>E</em><em>xponents</em>

25 - 2 × (-9) + 6          <em>next </em><em>M</em><em>ultiplication</em>

25 + 18 + 6              <em>next </em><em>A</em><em>ddition</em>

43 + 6 = 49

5 0
3 years ago
The distance DA between earth and the sun is 93,000,000 miles, the distance DE between earth and the moon is 240,000 miles, and
Rudiy27

Answer:

Hi

Step-by-step explaidknation:

6 0
3 years ago
A powerful women's group has claimed that men and women differ in attitudes about sexual discrimination. A group of 50 men (grou
MA_775_DIABLO [31]

Answer:

the lower limit is 35% women believed and 65% of men believed in serial discrimination

6 0
3 years ago
A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.
gayaneshka [121]

9514 1404 393

Answer:

  4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

  s = 16t²

So, the time required to fall distance s is ...

  t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

  s = 1100t

  t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

  (1/4)√s + s/1100 = 20

  275√s = 22000 -s . . . . . multiply by 1100 and subtract s

  75625s = s^2 -44000s +484,000,000 . . . square both sides

  s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

  s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

<em>Additional comment</em>

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0
3 years ago
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