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slavikrds [6]
3 years ago
7

Triangle ADE is enlarged to form triangle ABC. What is the scale factor?

Mathematics
1 answer:
LekaFEV [45]3 years ago
5 0
I need this answer to please when you get the answer will you let me know thank you!!
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Find the zeros (roots, x-intercepts) for each po<br> 3. f(x) = 5x^3- 20x
Aliun [14]

Answer:

v211

Step-by-step explanation:

6 0
3 years ago
If 3x^2-4x+7=0, then [x-2/3]^2=
Andrews [41]
I hope this helps you

7 0
3 years ago
2. Solve the equation using the quadratic<br> formula.<br> -4x2 + 40x + 16 = 0<br> Page 1 of 2
kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

<em><u>Solution:</u></em>

Given equation is:

-4x^2 + 40x + 16 = 0

To find: solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16

<u><em>Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,</em></u>

\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0
3 years ago
Given that
MissTica

Answer:

-2                                        

Step-by-step explanation:

Hey there!!

if we evaluate the expression it will look like :

3x + 14 = 8

and if we solve it:

3x+14=8

Step 1: Subtract 14 from both sides.

3x+14−14=8−14

3x=−6

Step 2: Divide both sides by 3.

3x/3 = -6/3

x= −2

4 0
3 years ago
What is the area of a rectangle that is 1/2 of a meter long and 3/8 of a meter wide?
Margarita [4]

Answer:

Step-by-step explanation:

note : the area of a rectangle  is : A = L ×W

L : lenght    W  : the width

A = (1/2)(3/8) = 3/16 m²

4 0
3 years ago
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