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slavikrds [6]
3 years ago
7

Triangle ADE is enlarged to form triangle ABC. What is the scale factor?

Mathematics
1 answer:
LekaFEV [45]3 years ago
5 0
I need this answer to please when you get the answer will you let me know thank you!!
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The discriminant of a quadartic equation is 40. What is the nature of the solutions?
o-na [289]

Since the discriminant is positive, this means we have two distinct real solutions.

If a, b, and c are rational numbers, then a discriminant of D = 40 indicates the two solutions are not rational. We would need D to be a perfect square to get two rational solutions.

8 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Snowcat [4.5K]

Hi!

---------------------------------------------------------------------------------------------

Area of a triangle = (base * height)/2

Area of a square = (side)^2

---------------------------------------------------------------------------------------------

QUESTION 1: Determine the area of the triangular face.

\frac{bh}{2}

32(20)/2

640/2

320

<u>The triangular face is 320 square feet.</u>

---------------------------------------------------------------------------------------------

QUESTION 2: Determine the surface area of the entire figure.

a^2

32^2

1024

<em>Now, add the 4 triangular faces to the area of the square face.</em>

1024+320(4)

1024+1280

2304

<u>The total surface area is 1204 square feet.</u>

---------------------------------------------------------------------------------------------

<u><em></em></u>

<u><em>For more information, see:</em></u>

brainly.com/question/4637102

brainly.com/question/22971514

5 0
3 years ago
20 time 1000 time 8898 time 2345 divided by 10
Artemon [7]
The answer is 41731620000
3 0
3 years ago
Let y = (2 6) and u = (7 1). Write y as the sum of a vector in Span(u) and a vector orthogonal to .
Minchanka [31]

The question is missing. Here is the complete question.

Let y = \left[\begin{array}{ccc}2\\6\end{array}\right] and u = \left[\begin{array}{ccc}7\\1\end{array}\right]. Write y as the sum of a vector in Span(u) and a vector orthogonal to u.

Answer: y = \left[\begin{array}{ccc}\frac{21}{10} \\ \frac{3}{10} \end{array}\right] + \left[\begin{array}{ccc}\frac{-1}{10}\\ \frac{57}{10} \end{array}\right]

Step-by-step explanation: The sum of vectors is given by

y =  y_{1} + z

where  y_{1} is in Span(u);

vector z is orthogonal to it;

First you have to compute the orthogonal projection y_{1} of y:

y_{1} = proj y = \frac{y.u}{u.u}.u

Calculating orthogonal projection:

\left[\begin{array}{c}2\\6\end{array}\right].\left[\begin{array}{c}7\\1\end{array}\right] = \left[\begin{array}{c}9\\6\end{array}\right]

\left[\begin{array}{c}7\\1\end{array}\right].\left[\begin{array}{c}7\\1\end{array}\right] = \left[\begin{array}{c}49\\1\end{array}\right]

y_{1} = \frac{9+6}{49+1}.u

y_{1} = \frac{15}{50}.u

y_{1} = \frac{3}{10}.u

y_{1} = \frac{3}{10}.\left[\begin{array}{c}7\\1\end{array}\right]

y_{1} = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]

Calculating vector z:

z = y - y_{1}

z = \left[\begin{array}{c}2\\6\end{array}\right] - \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]

z = \left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]

Writing y as the sum:

y = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right] + \left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]

5 0
3 years ago
Find the product of the expression. (6qr2) • (2qr)
zaharov [31]

here it is my answer

hope it is right

5 0
4 years ago
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