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Naddika [18.5K]
3 years ago
13

You can choose between two telephone companies. Company A has a monthly charge of $10 plus 5¢ a minute for each minute of long d

istance calls. Company B has a monthly charge of $8 plus 6¢ a minute for long distance calls. How many minutes must you use to make Company A a better deal
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer: Company A would be a better deal for number of minutes over 200

Step-by-step explanation:

Let x represent the number of minutes that you would use with either company A or company B.

Company A has a monthly charge of $10 plus 5¢ a minute for each minute of long distance calls. It means that the cost of x minutes of long distance call is

10 + 0.05x

Company B has a monthly charge of $8 plus 6¢ a minute for long distance calls. It means that the cost of x minutes of long distance call is 10 + 0.05x

8 + 0.06x

For Company A to be a better deal, it means that

10 + 0.05x < 8 + 0.06x

10 - 8 < 0.06x - 0.05x

2 < 0.01x

0.01x > 2

x > 2/0.01

x > 200

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nikitadnepr [17]

Answer:

<u>Rounding to the next whole, 33 persons completed the registration</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of e-mails sent out = 20,000

Number of e-mails opened = 6%

Number of e-mails that clicked on the link to register = 9% of the 6%

Number of e-mails that completed the registration = 30% of 9% of 6%

2.  How many people completed the registration​?

Let's do all the calculations to answer the question, this way:

Number of e-mails opened = 6 % of 20,000

Number of e-mails opened =0.06 * 20,000 = 1,200

Number of e-mails that clicked on the link to register = 9% of the 6%

Number of e-mails that clicked on the link to register = 0.09 * 1,200 = 108

Number of e-mails that completed the registration = 30% of 9% of 6%

Number of e-mails that completed the registration = 0.3 * 108 = 32.4

<u>Rounding to the next whole, 33 persons completed the registration</u>

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3 years ago
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Note:

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