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Naddika [18.5K]
3 years ago
13

You can choose between two telephone companies. Company A has a monthly charge of $10 plus 5¢ a minute for each minute of long d

istance calls. Company B has a monthly charge of $8 plus 6¢ a minute for long distance calls. How many minutes must you use to make Company A a better deal
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer: Company A would be a better deal for number of minutes over 200

Step-by-step explanation:

Let x represent the number of minutes that you would use with either company A or company B.

Company A has a monthly charge of $10 plus 5¢ a minute for each minute of long distance calls. It means that the cost of x minutes of long distance call is

10 + 0.05x

Company B has a monthly charge of $8 plus 6¢ a minute for long distance calls. It means that the cost of x minutes of long distance call is 10 + 0.05x

8 + 0.06x

For Company A to be a better deal, it means that

10 + 0.05x < 8 + 0.06x

10 - 8 < 0.06x - 0.05x

2 < 0.01x

0.01x > 2

x > 2/0.01

x > 200

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Allisa [31]

There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

<em>Let us tackle the problem!</em>

\texttt{ }

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}

\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}

\texttt{ }

<em>There were 5 project managers for every 50 engineers.</em>

\texttt{50 engineers} \rightarrow \texttt{5 project managers}

\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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3 years ago
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