Answer:
5 times
Step-by-step explanation:
Since it is 2.75 dollars per ride if you multiply 2.75 times 5 you get $13.75 and you cant add anymore.
This is no mistake he is the one
Dear Mathee2, you can do 1/10+1 8/10≈2 and 1/20+1 19/20≈2. Note: you said fractions, so did you want the fractions to be mixed numbers or improper fractions?
The direction of the difference between the 2 measurements.
<h3>What is nominal and ordinal scale with example?</h3>
- Examples of data for a nominal scale include a person's gender, ethnicity, and hair color.
- On the other hand, an ordinal scale requires putting data in a certain order, or in relation to one another and "ranking" each parameter (variable).
<h3>What is the difference nominal and ordinal?</h3>
- Ordinal data has a preset or natural order, whereas nominal data is categorized without a natural order or rank.
- A number that can be measured, however, will always be present in numerical or quantitative data.
<h3>What is an example of a ordinal scale?</h3>
- First place would go to a student with a score of 99 out of 100; third place would go to a student with a score of 92 out of 100; and so on.
Learn more about ordinal scale and nominal scale here:
brainly.com/question/15998581
#SPJ4
Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,

Where, p is the probability of success 
q is the probability of failure q=1-p, 
n is total number of trials n=8
r=3
Substitute the values,




Therefore, the probability that 8 mice are required is 0.2428.