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ruslelena [56]
4 years ago
14

A hard drive with a spin speed of 7200 RPM, commences spinning at time = 0, at time = 1.326 ms what is the angle that the disk h

as rotated by relative to it's start position?
I. In degrees

II. In Radians
Computers and Technology
1 answer:
Flura [38]4 years ago
7 0

Answer: I. 57º 17'   II. 1 rad.

Explanation:

A spin speed, implies the relationship between the angle rotated and the time  that has been spinning, which is equal, by definition, to the angular velocity.

ω = Δ∅ / Δt

In order to get the angle rotated in degrees, we need to convert first from RPM (revolutions per minute) to º/sec, as follows:

7200 rev/min *( 1 min/60 sec)* (360º/ 1 rev) = 7200* 6= 43200 º/s

Now, we know that the time passed since it started to spin, was 1.326 msec, i.e., 0.001326 sec.

Remembering that  ω = Δ∅ / Δt, solving for Δ∅, we get:

Δ∅ = 43200 º /s * 0.001326 sec = 57º 17'

II. In order to get the answer in rads, we can convert the rpm to rads/sec, as follows:

7200 rev/min *( 1 min/60 sec)* (2 π/ 1 rev) = 240 π rad/sec.

Applying the same equation as above, we get:

Δ∅ = 240 π rad/s * 0.001326 sec = 1 rad.

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