For this case we have the following expression:
3x ^ 2y ^ 2-6xz / 6x ^ 2yz
From here, we must exclude all values that make the denominator equal to zero.
We have then:
6x ^ 2yz = 0
Therefore, the results are:
x = 0
y = 0
z = 0
Answer:
The exclusion that fits best with this problem is:
x, y, z = 0
Answer:
the second one
Step-by-step explanation:
The answer would be: a > 2
We calculate the speed by dividing the distance over time:
s = d/t
So the distance described in the problem is always the same, A to B and B to A.
But we are told that;
7 = d/t
7 = 2d/(t + 2)
that is, the first equation say that at speed 7 km/h a distance d is walked in a time t
the second equation say that at a average speed of 7 (that is 8 on one way and 6 in the other: 8 + 6 = 14, half of it), twice the distance is walked in a time equal to the first time plus 2 minutes.
So we have a system of linear equations, 2 of them with two unknowns, we can solve that:
7 = d/t
7 = 2d/(t + 2<span>)
</span>lets simplify them:
7t = d
7(t + 2) = 2d
7t = 2d - 14
we substitute the first in the second:
<span>7t = 2d - 14
</span><span>7t = d
</span>so:
d = 2d - 14
d = 14
so the distance between A and B is 14 km
Answer:
it requires 280 ton of wood
Step-by-step explanation:
one ship can accommodate 300 sailors so for 2100 sailors you need
2100/300
7 ships
and as I ship require 40 tons of wood then 7*40
280 tons
then
he can get 4 ton of wood per day
then
280/4
70 days
therefore he needs wood for 70 days to accommodate 2100 sailors
