Question

Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25,

Answer 1

Answer:

Step-by-step explanation:

If the smallest integer is x, the next odd number would be x + 2, and the largest would be x + 4.  The sum of the largest (x+4) and twice the smallest (2x) is 25.  The equation for that would be (x+4)+2x=25 which is 3x + 4 = 25.  Not sure how far you have to go with it.  But that equation could be solved for x.