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Andreas93 [3]
3 years ago
10

Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25,

Mathematics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

Step-by-step explanation:

If the smallest integer is x, the next odd number would be x + 2, and the largest would be x + 4.  The sum of the largest (x+4) and twice the smallest (2x) is 25.  The equation for that would be (x+4)+2x=25 which is 3x + 4 = 25.  Not sure how far you have to go with it.  But that equation could be solved for x.

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damaskus [11]

Answer:

P(Green\ and\ Green) = \frac{25}{144}

Step-by-step explanation:

Given

Green=5

Blue = 7

Required

P(Green\ and\ Green)

This is calculated as:

P(Green\ and\ Green) = P(Green) * P(Green)

Since, it is a probability with replacement, we have:

P(Green\ and\ Green) = \frac{Green}{Total} * \frac{Green}{Total}

So, we have:

P(Green\ and\ Green) = \frac{5}{12} * \frac{5}{12}

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Total = 500 * ([(1 + .07)^26 -1] / .07) -500
Total = 500 * (<span><span>4.8073529249 </span> / .07) -500
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Source:
http://www.1728.org/annuity.htm

</span>

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