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Andreas93 [3]
3 years ago
10

Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25,

Mathematics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

Step-by-step explanation:

If the smallest integer is x, the next odd number would be x + 2, and the largest would be x + 4.  The sum of the largest (x+4) and twice the smallest (2x) is 25.  The equation for that would be (x+4)+2x=25 which is 3x + 4 = 25.  Not sure how far you have to go with it.  But that equation could be solved for x.

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3. If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day is: (a) 1 – n
zaharov [31]

Answer:

If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day

will be \frac{1}{n}.

Step-by-step explanation:

From the question, it is clear that

  • If ‘A’ can finish a work in ‘n’ days, then
  • we have to determine the part of work finished in 1 day.

So

let 'n' be the number of days A takes to complete the whole work

Let the whole job be denoted as '1'

Thus, the part of work finished in 1 day will be:

                      \:\frac{Total\:work}{Time\:taken\:by\:A\:to\:complete\:the\:work}\:=\frac{1}{n}

Therefore, If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day will be \frac{1}{n}.

                             

Keywords: work, word problem

Learn more about word problem form brainly.com/question/12419898

#learnwithBrainly

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3 years ago
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