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3 years ago

10

Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25,

1 answer:

rusak2 [61]3 years ago

4 0

Answer:

Step-by-step explanation:

If the smallest integer is x, the next odd number would be x + 2, and the largest would be x + 4. The sum of the largest (x+4) and twice the smallest (2x) is 25. The equation for that would be (x+4)+2x=25 which is 3x + 4 = 25. Not sure how far you have to go with it. But that equation could be solved for x.

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