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Amiraneli [1.4K]
3 years ago
6

The volume of a cylinder is 4pix^3 cubic units and its height is x units.

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

r = 2x

Step-by-step explanation:

The volume of the cylinder is given by the following formula:

V = \pi\cdot r^{2}\cdot h

By comparing each variable, height and radius of the cylinder are, respectively:

h = x

r = 2x

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20 Points + Brainliest for the answer and Explanation!!!
Vlad1618 [11]

Answer:

P+Q=5x^2+4

Q-P=-x^2-4x+16

Step-by-step explanation:

We are given

P=3x^2+2x-6

Q=2x^2-2x+10

Calculation of P+Q:

P+Q=3x^2+2x-6+2x^2-2x+10

now, we can combine like terms

P+Q=3x^2+2x^2+2x-2x+10-6

P+Q=5x^2+0+4

P+Q=5x^2+4

Calculation of Q-P:

Q-P=2x^2-2x+10-(3x^2+2x-6)

Firstly, we will distribute negative sign

Q-P=2x^2-2x+10-3x^2-2x+6

now, we can combine like terms

Q-P=2x^2-3x^2-2x-2x+6+10

Q-P=-x^2-4x+16

8 0
2 years ago
A large brine tank containing a solution of salt and water is being diluted with fresh water. The relationship between the elaps
kati45 [8]

Answer: 5.97 hours

Step-by-step explanation:

S(t) = 100

I put in 100 = 600 x e^-0.3t and it came out to be 5.97 when rounded to the nearest hundredth. It is also correct on khan academy.

7 0
3 years ago
the minute hand of a clock is 5 inches long. what is the area of the circle, in square inches, created in a hand sweep in an hou
ira [324]
Solve the area of the whole circle since in an hour, the minute hand covers the whole clock
assuming that the minute hand reaches all the way out to the edge of the clock


the minute hand is the radius
area=pi times r^2
r=5
5^2=25
area=pi times 25
area=25pi

aprox pi=3.14
25 times 2.14=78.5

area=78.5 in^2
6 0
3 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
PLS HELP DUE AT MIDNIGHT
Fudgin [204]

Answer:

Is this a supplementary angle? if yes let me know so that i can help you

4 0
3 years ago
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