What is the range of the function f(x) = |x| +2?
1 answer:
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Answer:
P(x=2) = 0.2368
Step-by-step explanation:
given data
stocks of local interest N = 20
stocks increased K = 10
stocks decreased = 5
remained unchanged = 5
solution
we take here no of stock that are increased randomly n = 2
so here Hypergeometric random variable can take integer value
{max(0, n+k - N ), min(n,K) } = {0,2}
so here
P(x=2)
so
P(x=k) = .......................1
P(x=2 ) =
solve it we get
P(x=2 ) = 0.236842
now we use excel function as
HYPGEOM.DIST (k,n,N.cumulative) .....................2
so it will be
HYPGEOM.DIST (2,2,10,,false)
we get
HYPGEOM.DIST (2,2,10,,false) = 0.236842
so
P(x=2) = 0.2368
Answer:
the answer is A.
Step-by-step explanation:
(×
)÷
2×9= 18
6+6= 12
÷
=